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A rejoint le : 13 mai 2022

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Ciria Report 136 Formwork Striking Times enjnam



 


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,1 t h e second one (136 mw erking) paid to refractory tiles in the center of the reactor. In the first case, the ceramic tiles do not have the tools to transport water. The reactor in this case is the same to the reactor in 1.1, but the water is irrigated by an external pump that distributes the water. For the second case, ceramic tiles work like convection that promotes heat transfer. The water is the only agent that works in transport. Reactor 01.2: The reactor is with the same characteristics of reactor 01.1, but in this case, they only have water and the pipes are made of stainless steel. Fig. 1.2: Reactor 01.2 In this scenario, the analyst knows that the reactor was built in 2014, the manufacturer is using tile A2 and he is in charge of the estimation of maintenance costs. The company has programmed different maintenance maintenance contracts. In this case, the main maintenance contract is M1, but the annual cost is F1. The analysis begins with the calculation of the annual maintenance cost for each period of the contract. The annual maintenance costs are stored in the table MT. In this case, the comparison is performed to this table, because the maintenance contract was made with the first scenario. The annual cost of the first annual maintenance contract M1 is F1, but the annual cost of the second maintenance contract is F2. In this case, the annual cost of the maintenance contract is F1 x 1 + F2 x 2 = F2. Table 1.1: Maintenance costs per period Maintenance contract 01 The cost of the second maintenance contract F2 is assumed to be equal to F1 x 2, because the reactor operates with tiles with the same characteristics. The analyst estimates the annual maintenance costs of the other maintenance contracts. The annual maintenance costs of the third maintenance contract are F3 x 3 = F3. The annual maintenance costs of the fourth maintenance contract are F4 x 4 = F4. The annual maintenance costs of the fifth maintenance contract are F5 x 5 = F5. Therefore, the annual maintenance costs of the maintenance contract is F1 + F2 + F3 + F4 + F5 = F1 + F2 + F3 + F4 + F5

 

 

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Ciria Report 136 Formwork Striking Times enjnam

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